Posted by **ximena** on Thursday, October 21, 2010 at 12:38am.

things do not go quite as planned. you invested $8000, part of it in stock that paid 12% annual interest. however, the rest of the money suffered a 55 loss. if the total annual income from both investments was $620, how much was invested at each rate?

- math -
**Reiny**, Thursday, October 21, 2010 at 8:50am
Since the total profit was 620 which included the loss of 55, there must have been a profit of 675 from the first investment.

Assuming we are looking only at the one year, the question now becomes a simple interest problem where

P ?

I = 675

R = .12

T = 1

P = I/(RT)

= 675/.12 = 5625

so he invested $5625 at 12% ( the winner) and

$2375 in the losing investment.

- math -
**marlen**, Thursday, March 10, 2011 at 11:01pm
what is 9000at 3%simple interest for 2and 1/2

## Answer This Question

## Related Questions

- College algebra - Things did not go quite as planned. you invested $8,000, part ...
- algebra - you invested $8000, part of it in stock that paid 12% annual interest...
- math - Rosa invested $8000 for one year, part ast 8% annual interest and the ...
- Math - Rosa invested $8000 for one year, part ast 8% annual interest and the ...
- algebra - Calvin invested $7500 for one year, part 12% annual interest and the ...
- algebra - HELP! Please Calvin invested $7500 for one year, part 12% annual ...
- math - An investment of $3,000 is made at an annual simple interest of 5%. How ...
- Math - tracy invested $6000 for one year, part at 10% annual and the balance at ...
- math - A total of $8000 is invested: part at 8% and the remainder at 12% . How ...
- algebra - Larry Mitchel invested part of his $32,000 advance at 7% annual simple...

More Related Questions