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Physics

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A car drives straight off the edge of a cliff that is 58 m high. The police at the scene of the accident note that the point of impact is 126 m from the base of the cliff. How fast was the car traveling when it went over the cliff?

  • Physics - ,

    The height of the bldg and the point
    where the car hits the ground form the ver and hor sides of a rt triangle.
    The distance is = to the hyp.

    tanA = y / x,
    tanA = 58 / 126 = 0.4603,
    A =24.7 deg,

    d = x /cosA = 126 / cos24.7 =138.7 m.

    V^2 = 2gd,
    V^2 = 2 * 9.8 * 138.7 = 2718.5,
    V = sqrt(2718.5) = 52.1 m/s.

  • Physics - ,

    ^wrong!

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