Posted by Ash on Wednesday, October 20, 2010 at 4:43pm.
S + O2 ==> SxOy
S start = 50.00 grams.
SxOy = 100.00 grams.
Therefore, we must have added 50.00 g oxygen.
mols S = 50/32.066 = 1.56
moles O = 50/16 = 3.125
Now find the ratio of the two to each other. The easy way is to divide the smaller number by itself.
1.56/1.56 = 1.000 (you do this to get 1.00 and it works every time. :-),
Then divide the other number by the same small number.
3.125/1.56 = 2.004.
Now round those to whole numbers and you have the formula of S1O2 or SO2.
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