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September 20, 2014

September 20, 2014

Posted by **JoniAnne** on Wednesday, October 20, 2010 at 4:36pm.

Please check-

Solve 3 > sqrt(3x)

3x >=o

x>=0/3

x>=0

square both sides and you have 3x < 3^2

3x,9

x<9/3

x<3

answer is 0<=x<3 correct or not?

3(cube) sqrt(2-5) = 3

cube both sides = 2-5x = 27

-5x = 25

x = -5, correct?

Thank you

- Algebra-Please check-I'm desperate -
**bobpursley**, Wednesday, October 20, 2010 at 4:50pmyes, on the 0=<x=<3

On the

3^3 sqrt (2-5x)=3

Hmmm. I dont know what you meant on the statement.

did you have

cbrt(2-5x)=3 ? if so

2-5x=27

-5x=25

x=-5

- Algebra-Please check-I'm desperate -
**JoniAnne**, Wednesday, October 20, 2010 at 5:06pmYes, that's what I meant for the second one-thank you for replying

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