At Irv's Cycle Rental Shop, Irv renst all knids of cycles: unicyles, tandem bikes, regualr bikes, and even tricycles for little kids. He parks all the cycles in front of the shop with a helmet for each rider strapped to the cycles. This morninf Irv counted 57 helments and 115 wheels parked in front of his store. He knows he has an equal number of unicycles and tandem bikes. He also knows that he has 32 regular bikes. How many unicycle, tandem bikes, and tricycles does Irv have?

It's hard to believe you're serious about wanting help when you've posted this at least twice with the same 6 typos/spelling errors.

what do u mean????

To solve this problem, we can set up a system of equations based on the given information. Let's denote the number of unicycles as 'u', the number of tandem bikes as 't', and the number of tricycles as 'c'.

From the information given in the question, we know:
1. The number of helmets is equal to the sum of the number of unicycles, tandem bikes, and tricycles.
So, u + t + c = 57.

2. The number of wheels is equal to the sum of the (number of unicycles * 1) + (number of tandem bikes * 2) + (number of regular bikes * 2) + (number of tricycles * 3).
So, (u + t) * 1 + (32 * 2) + c * 3 = 115.

We have two equations with two variables, so we can solve them simultaneously.

1. Rearranging the first equation, we get:
u + t = 57 - c.

2. Substituting this value in the second equation, we get:
(u + t) * 1 + (32 * 2) + c * 3 = 115.
(57 - c) * 1 + (32 * 2) + c * 3 = 115.

Simplifying, we get:
57 - c + 64 + 3c = 115.
5c + 121 = 115.

Solving for c, we get:
5c = 115 - 121.
5c = -6.
c = -6/5.
c = -1.2.

This is not a valid solution since the number of cycles cannot be negative. Therefore, it seems there may be a mistake in the given information or question. Please double-check the data provided.