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December 20, 2014

December 20, 2014

Posted by **JoniAnne** on Wednesday, October 20, 2010 at 3:08pm.

Please check-

Solve 3 > sqrt(3x)

3x >=o

x>=o/3

x>=0

square both sides and you have 3x < 3^2

3x,9

x<9/3

x<3

answer is 0<=x<3 correct or not?

3(cube) sqrt(2-5) = 3

cube both sides = 2-5x = 27

-5x = 25

x = -5, correct?

Thank you

- Algebra-Please check my work -
**Reiny**, Wednesday, October 20, 2010 at 5:44pmyes, correct

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