Balance the net ionic equation
I− + NO−
2 ! NO + I2
(in acidic solution). What is the sum of the
coefficients? Use H+ rather than H3O+ where
appropriate.
1. 13
2. 15
3. 17
4. 11
5. 19
You need to learn how to do these instead of us giving you the answer. What is your big hang up with these?
This is the first time I've submitted a question and I just need some help with this one.
To balance the net ionic equation, we need to ensure that the number of atoms of each element is equal on both sides of the equation.
Given the unbalanced equation:
I- + NO-2 -> NO + I2
We can start by balancing the iodine (I) atoms since it appears on both sides. There is one I atom on the left side and two on the right side, so we need to put a coefficient of 2 in front of I- on the left side:
2I- + NO-2 -> NO + I2
Next, let's balance the oxygen (O) atoms. There are two O atoms in NO-2 on the left side, so we need to add one O atom to the right side by placing an H2O molecule on the right:
2I- + NO-2 -> NO + I2 + H2O
Now, let's balance the hydrogen (H) atoms. There is one H atom in H2O on the right side, so we need to add two H atoms on the left side by placing an H+ ion on the left:
2I- + NO-2 + 2H+ -> NO + I2 + H2O
Finally, let's balance the charge. There are two negative charges on NO-2 on the left side, while there are two positive charges from the H+ ions on the right side. To balance the charges, we can add two electrons (2e-) to the left side of the equation:
2I- + NO-2 + 2H+ + 2e- -> NO + I2 + H2O
This is the balanced net ionic equation. Now, let's find the sum of the coefficients: 2 + 1 + 2 + 2 + 2 + 1 = 10.
Therefore, none of the options provided (1. 13, 2. 15, 3. 17, 4. 11, 5. 19) is the correct answer. The correct answer should be 10.