Chemistry
posted by Brittany on .
A 26.7 g sample of ethylene glycol, a car radiator coolant, loses 668 J of heat. What was the initial temperature of ethylene glycol if the final temperature is 32.5°C (c of ethylene glycol = 2.42 J/gK)?

q = mass e.g. x specific heat e.g. x (TfinalTinitial)

668= 26.7(2.42)(X32.5) ?

If Tfinal is 32.5 and Tinitial is X, it appears you have reversed the numbers. I have
668 = 26.7(2.42)(32.5X)
However, you reversed the sign on TfinalTinitial AND you used a + instead of a  sign for heat lost of 668 so the sign turns out ok as well as the number. 
what is the answer????????