Posted by Jamie on Wednesday, October 20, 2010 at 10:07am.
Use your log rules
(3^x)(4^2x+1)=(6^x+2)
log[(3^x)(4^2x+1)]= log(6^x+2)
xlog3 + (2x+1)log4 = (x+2)log6
xlog3 + x(2log4) + log4 = xlog6 + 2log4
x(log3 + 2log4 - log6) = 2log4 - log4
x(log8) = log9
x = log9/log8
Thank you so much! I got to the third step and then couldn't figure out how to go about it without using decimals..but thanks so much!
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