Tuesday

March 3, 2015

March 3, 2015

Posted by **tony** on Wednesday, October 20, 2010 at 2:31am.

- physics -
**drwls**, Wednesday, October 20, 2010 at 6:46amAt the bottom of the ramp, the block has acquired kinetic energy MgH, where H = 1.5 - 0.25 = 1.25 m.

Its velocity is therefore

V = sqrt(2gH) = 4.95 m/s

Multiply that (horizontal) velocity by the time it takes to fall H' = 0.25 m vertically.

T = sqrt (2H'/g) = 0.051 s

That will give you the distance d.

d = sqrt (2gH) * sqrt (2H'/g)

= 2 sqrt(H*H')

It is interesting that d is independent of g. If g were zero, it would not fall down the ramp at all

- physics -
**Amir**, Thursday, November 11, 2010 at 11:22pmA 2 kg box slides down a 25 degree ramp with an acceleration of 2 meters per second. Determine the coefficient of kinetic friction between the box and the ramp?

**Answer this Question**

**Related Questions**

physics - A 1.9- block slides down a frictionless ramp, as shown in the figure. ...

physics - A 1.80-kg block slides down a frictionless ramp.The top of the ramp is...

physics - I am having great difficulty with this question. A block is placed on ...

Physics - A block is placed on a frictionless ramp at a height of 14.5 m above ...

physics - A 2.7 kg block, starting from rest, slides down a ramp with friction. ...

Physics - A 50 gram block is placed on a frictionless ramp 2 meters above the ...

physics - A block slides down a frictionless ramp. If the ramp angle is 22 ...

physics - a small block of mass M=0.050 kg is released from rest at the top (h=0...

mechanics - A 2kg box starts from rest and slides down an incline as shown in ...

physics - A box of mass 5.0 kg starting from rest slides down a 1.8 m long ramp ...