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trig

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how do i find six trig functions for cos(pi over 2-x)=3/5, cos x=4/5?

  • trig - ,

    given cos x = 4/5
    by making a diagram, you should recognize the 3,4,5 right-angles triangle
    secondly, the cosine is positive in quadrants I and IV

    in I:
    sinx = 3/5 , csc x = 5/3
    cosx = 4/5 , sec x = 5/4
    tanx = 4/3 , cot x = 3/4

    you do IV


    back to cos(pi over 2-x)=3/5
    cos (π/2 - x) = 3/5
    (cosπ/2)(cosx) + (sinπ/2)(sinx)= 3/5
    sinx = 3/5
    (hey, we knew that!)

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