Can someone help me with this problem, plz....

12b^8/ 3b^4=

Use the laws of exponents:

Laws of exponents:
xa*xb = xa+b
xa/xb = xa-b
(xa)b = xab
x-a = 1/xa
x1/a = ath root of x

12b^8/ 3b^4
= (12/3)b^8/b^4
= 4b8-4
= 4b4