Posted by Anonymous on Tuesday, October 19, 2010 at 3:50pm.
So P is pointing UP?
If so, a portion of P counters weight, and in so doing, reduces friction to zero.
Psin30=mg
P= 2mg
If the net force is zero, the friction force balances the horizontal component of the applied force P.
Calculate the Friction force and divide it by cos 30.
The fact that the applied force is 30 deg below horizontal will affect the friction force.
My interpretation of the problem is different from Bob's. I did not assume that the friction was reduced to zero, only that it balances the applied force to make the net force (and work) zero.
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