I need help with this question please. Draw the structure of triacylglycerol formed from oleic acid, linoleic acid, and stearic acid. Give balanced equation and show how much hydrogen would be needed to reduce the triacylglycerol completely, show the product.

To draw the structure of a triacylglycerol formed from oleic acid, linoleic acid, and stearic acid, we need to know the chemical formula for each fatty acid. Here are their chemical formulas:

Oleic acid: C18H34O2
Linoleic acid: C18H32O2
Stearic acid: C18H36O2

In a triacylglycerol, three fatty acids are bonded to a glycerol molecule. The glycerol molecule has a chemical formula of C3H8O3.

To draw the structure of the triacylglycerol, we can use the following representation:

O
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O-C-C-C-O
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R R R
(oleic) (linoleic) (stearic)

In this structure, the "R" represents the fatty acid chains, which are attached to the glycerol molecule. You would need to connect the appropriate R group to each carbon atom of the glycerol molecule.

Now, let's move on to the balanced equation for the complete reduction of the triacylglycerol. When hydrogen is used to reduce a triacylglycerol, it breaks down into glycerol and fatty acids. The balanced equation for the complete reduction would be:

Triacylglycerol + 3H2 -> 3Fatty Acids + Glycerol

Now, let's calculate how much hydrogen would be needed to completely reduce the triacylglycerol. Since the triacylglycerol consists of three fatty acids, you would need 3 moles of hydrogen gas (H2) for each mole of triacylglycerol.

Since 1 mole of any substance is equal to its molar mass in grams, we can calculate the molar mass of the triacylglycerol. Summing the molar masses of oleic acid, linoleic acid, and stearic acid:

Molar mass of triacylglycerol = (molar mass of oleic acid + molar mass of linoleic acid + molar mass of stearic acid) + molar mass of glycerol.

Using the atomic masses from the periodic table, we can calculate the molar masses as follows:

Molar mass of oleic acid = (18 x atomic mass of carbon) + (34 x atomic mass of hydrogen) + (2 x atomic mass of oxygen)
Molar mass of linoleic acid = (18 x atomic mass of carbon) + (32 x atomic mass of hydrogen) + (2 x atomic mass of oxygen)
Molar mass of stearic acid = (18 x atomic mass of carbon) + (36 x atomic mass of hydrogen) + (2 x atomic mass of oxygen)

The molar mass of glycerol is calculated similarly:

Molar mass of glycerol = (3 x atomic mass of carbon) + (8 x atomic mass of hydrogen) + (3 x atomic mass of oxygen)

Add the molar masses of the glycerol and the three fatty acids to get the total molar mass of the triacylglycerol.

Next, calculate the moles of triacylglycerol using the given mass or the molar quantity. Once you have the moles of the triacylglycerol, you can multiply it by 3 to get the moles of hydrogen required for complete reduction.

Finally, to show the product, you would have 3 moles of fatty acids and 1 mole of glycerol formed.

I hope these step-by-step instructions help you draw the structure of the triacylglycerol, provide the balanced equation, and calculate the amount of hydrogen required for complete reduction. Let me know if you need any further assistance!

To draw the structure of triacylglycerol formed from oleic acid, linoleic acid, and stearic acid, let's first understand the chemical structures of these fatty acids.

Oleic acid has the formula C18H34O2 and contains one double bond between carbon atoms. Linoleic acid has the formula C18H32O2 and contains two double bonds between carbon atoms. Stearic acid has the formula C18H36O2 and contains no double bonds.

Now, let's draw the structure of the triacylglycerol:

Oleic acid (C18H34O2) reacts with glycerol (C3H8O3) through esterification, which involves the removal of water, forming an ester bond. Since there are three fatty acid molecules (oleic acid, linoleic acid, and stearic acid) reacting with one glycerol molecule, we will have three ester bonds formed.

The esterification reaction can be represented by the following equation:

3 Oleyl alcohol + Glycerol → Triolein + 3 Water

Where "Oleyl alcohol" represents the fatty acid molecule during esterification.

The structure of triolein can be drawn by combining three oleic acid molecules with a glycerol molecule, as shown below:

H H H
| | |
O=C-O-(CH2)14-CH=CH-(CH2)7-CH=CH-(CH2)7-COO-CH2-CH(OH)-CH2-O-C(O)-(CH2)14-CH=CH-(CH2)7-CH=CH-(CH2)7-COO-CH2-CH(OH)-CH2-O-C(O)-(CH2)14-CH=CH-(CH2)7-CH=CH-(CH2)7-COOH

Now, let's consider the complete reduction of triolein (triacylglycerol) using hydrogen gas (H2).

Triolein + 3H2 → Glycerol + 3 Stearic acid

To calculate the amount of hydrogen needed to completely reduce triolein, we need to find the molar ratio between hydrogen and triolein.

The molar mass of triolein is approximately 885.5 g/mol, and the molar mass of hydrogen gas is 2.016 g/mol.

Therefore, the molar ratio between triolein and hydrogen gas is:

1 mole of triolein : 3 moles of hydrogen gas

Now, let's assume you have a certain mass of triolein (m) that needs to be completely reduced. To calculate the amount of hydrogen needed, we use the following equation:

Amount of Hydrogen (g) = (m / 885.5) * (3 * 2.016)

This equation considers the molar mass ratio and mass of triolein.

By solving this equation, you will get the amount of hydrogen (in grams) required to completely reduce the given mass of triolein.

After the complete reduction, you will obtain glycerol and three stearic acid molecules:

Glycerol: HO-CH2-CH(OH)-CH2-OH

Stearic acid: CH3-(CH2)16-COOH

I hope this explanation helps you understand how to draw the structure of triacylglycerol and calculate the amount of hydrogen needed for complete reduction.