Posted by tia on Tuesday, October 19, 2010 at 12:21pm.
solve the following pair of simultaneous equations.
2x3y=13
3x+y=3

maths  MathMate, Tuesday, October 19, 2010 at 12:40pm
By elimination:
2x3y=13 ...(1)
3x+y=3 ...(2)
Multiply (2) by 3 and add to (1)
2x3y=13 ...(1)
9x+3y=9 ...(3)
Add(1) and (3)
11x = 22 ...(4)
Solve (4) to get
x=11
Substitute x=11 in (1) to solve for y.

typo/error  Jen, Tuesday, October 19, 2010 at 2:53pm
x=2, Substitute x=2 in (1) or (2). 2 is easier.

maths  MathMate, Tuesday, October 19, 2010 at 5:11pm
Thank you Jen.
yes, x=2.
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