Posted by **tia** on Tuesday, October 19, 2010 at 12:21pm.

solve the following pair of simultaneous equations.

2x-3y=13

3x+y=3

- maths -
**MathMate**, Tuesday, October 19, 2010 at 12:40pm
By elimination:

2x-3y=13 ...(1)

3x+y=3 ...(2)

Multiply (2) by 3 and add to (1)

2x-3y=13 ...(1)

9x+3y=9 ...(3)

Add(1) and (3)

11x = 22 ...(4)

Solve (4) to get

x=11

Substitute x=11 in (1) to solve for y.

- typo/error -
**Jen**, Tuesday, October 19, 2010 at 2:53pm
x=2, Substitute x=2 in (1) or (2). 2 is easier.

- maths -
**MathMate**, Tuesday, October 19, 2010 at 5:11pm
Thank you Jen.

yes, x=2.

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