Posted by **JayLynne-Mathmate please recheck** on Tuesday, October 19, 2010 at 12:20pm.

When I asked you about the following problem:Solve 4sqrt(6x-2)>4

The first 4 is outside the square root sign and then (6x-2) is under the square root sign >4. You said to do the following. Divide by 4 to get

sqrt(6x-2)>1

For this to happen, 6x-2>1 or x>(1/2)

which does not match any of your answers.

I suspect there is a misprint or misinterpretation of the question.

Wouldn't I say (4sqrt(6x-2))^4 > 4^4 because I take

6x-2 > 256

6x>258

x >43

and 6x-2>=0

6x-2>=2

x>=1/3

but when I put 1/3 back in, I don't think it works, does it so that's why I said x>43 and not the other answers available which would be

1/3<=x<43

1/3<x<43

x>=1/3

x>43

- Algebra -
**JayLynne-Someone please recheck**, Tuesday, October 19, 2010 at 12:31pm
Could someone please recheck the solution to the above problem-Mathmate said it can't be done but I think it was just interpreted the wrong way-please recheck m solution

Thank you

- Algebra -
**MathMate**, Tuesday, October 19, 2010 at 12:46pm
If the expression was the fourth root, it would be more understandable to write it as:

(6x-2)^(1/4) > 4

in which case x>43 is the correct answer.

Alternatively, you could add a note to say that the left-hand-side is the fourth root.

- Algebra -
**JayLynne-Someone please recheck**, Tuesday, October 19, 2010 at 12:50pm
Thank you

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