Algebra

posted by on .

When I asked you about the following problem:Solve 4sqrt(6x-2)>4
The first 4 is outside the square root sign and then (6x-2) is under the square root sign >4. You said to do the following. Divide by 4 to get
sqrt(6x-2)>1
For this to happen, 6x-2>1 or x>(1/2)
which does not match any of your answers.
I suspect there is a misprint or misinterpretation of the question.

Wouldn't I say (4sqrt(6x-2))^4 > 4^4 because I take
6x-2 > 256
6x>258
x >43

and 6x-2>=0
6x-2>=2
x>=1/3
but when I put 1/3 back in, I don't think it works, does it so that's why I said x>43 and not the other answers available which would be
1/3<=x<43
1/3<x<43
x>=1/3
x>43

• Algebra - ,

Could someone please recheck the solution to the above problem-Mathmate said it can't be done but I think it was just interpreted the wrong way-please recheck m solution

Thank you

• Algebra - ,

If the expression was the fourth root, it would be more understandable to write it as:
(6x-2)^(1/4) > 4
in which case x>43 is the correct answer.
Alternatively, you could add a note to say that the left-hand-side is the fourth root.

• Algebra - ,

Thank you