Posted by JayLynneMathmate please recheck on .
When I asked you about the following problem:Solve 4sqrt(6x2)>4
The first 4 is outside the square root sign and then (6x2) is under the square root sign >4. You said to do the following. Divide by 4 to get
sqrt(6x2)>1
For this to happen, 6x2>1 or x>(1/2)
which does not match any of your answers.
I suspect there is a misprint or misinterpretation of the question.
Wouldn't I say (4sqrt(6x2))^4 > 4^4 because I take
6x2 > 256
6x>258
x >43
and 6x2>=0
6x2>=2
x>=1/3
but when I put 1/3 back in, I don't think it works, does it so that's why I said x>43 and not the other answers available which would be
1/3<=x<43
1/3<x<43
x>=1/3
x>43

Algebra 
JayLynneSomeone please recheck,
Could someone please recheck the solution to the above problemMathmate said it can't be done but I think it was just interpreted the wrong wayplease recheck m solution
Thank you 
Algebra 
MathMate,
If the expression was the fourth root, it would be more understandable to write it as:
(6x2)^(1/4) > 4
in which case x>43 is the correct answer.
Alternatively, you could add a note to say that the lefthandside is the fourth root. 
Algebra 
JayLynneSomeone please recheck,
Thank you