A 1.0 kg glass bowl at 37 °C is placed in a freezer. How much heat will the freezer have to remove from the bowl to take it to 0 °C? (cglass = 0.2 cal/deg-gm)
Q (heat) = M * C *(change in T)
M is the mass and C is the specific heat. You know all three quantitiies
Take it from there.
Would the change be a negative number?
Calculate the amount of heat required to heat a 45 sample of ethanol from 11.0 to 19.0. Specific heat capacity of ethanol is 2.42 .
7758030
To calculate the amount of heat that the freezer will have to remove from the glass bowl, we can use the formula:
Q = m * c * ΔT,
where:
Q is the amount of heat transferred,
m is the mass of the object,
c is the specific heat capacity of the material, and
ΔT is the change in temperature.
Given:
m = 1.0 kg (mass of the glass bowl)
c = 0.2 cal/deg-gm (specific heat capacity of glass)
ΔT = 37 °C - 0 °C = 37 °C (change in temperature)
Now, let's substitute the values into the formula:
Q = 1.0 kg * 0.2 cal/deg-gm * 37 °C
To simplify, convert the units:
1 cal = 4.184 J (conversion factor)
Q = 1.0 kg * 0.2 cal/deg-gm * 37 °C * 4.184 J/cal
Q = 31.0608 J
Therefore, the freezer will have to remove approximately 31.0608 Joules of heat from the bowl to decrease its temperature from 37 °C to 0 °C.