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April 16, 2014

April 16, 2014

Posted by **daani** on Tuesday, October 19, 2010 at 11:58am.

- calculus -
**MathMate**, Tuesday, October 19, 2010 at 12:09pmThe vertex is on the ground, so the tank is in a funnel position.

Let the water height be h, then the radius of the surface of water is r(h)=10h/24=5h/12

The volume at a height of h is

V(h)=(π/3)r(h)² h

=(π/3)(5h/12)² h

=(25π/432)h³

Differentiate with respect to time, t

dV(h)/dt

=(25π/432)*3h²dh/dt

=(25π/144)h² dh/dt

Since dV(h)/dt is known (=20 ft³/min), you can solve for dh/dt.

Note that the unit of dh/dt is in ft/min.

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