AlgebraPlease check my calculations
posted by JayLynneI had misprint in previous posting on .
Could you please check my answers and help with the ones I can't figure out
1. Solution to the radical function sqrt(1/2x+1) = 1 is x = 0
True or False I think it is true according to my calculations
2.Solve x = sqrt(8x)
8x = x^2
x^2  8x = 0
x(x8) = 0
x = 0
x8 =0
x=8
the only solution is x = 0, correct or nobecause x = 8 doesn't work
3. Simply (3x^2y^2)^2/9x^5y
a.xy^3
b. xy^3/3
xy^3/9
d. xy^3/81
I think it is xy^3/81 but I'm not sure of my calculations
4. Solve 4sqrt(6x2)>4
a. 1/3<=x<43
b. 1/3<x<43
x>=43
x>43
I think x>43
Thank you

1. true if the equation is
sqrt((1/2)x+1) = 1, or
sqrt(x/2+1) = 1
2. x=√(8x)
"the only solution is x = 0, correct or nobecause x = 8 doesn't work " ???
x=0 works: 0=√(8*0)
x=8 also works √(8*8)=8
3. Correct.
4. Solve 4sqrt(6x2)>4
Divide by 4 to get
sqrt(6x2)>1
For this to happen, 6x2>1 or x>(1/2)
which does not match any of your answers.
I suspect there is a misprint or misinterpretation of the question.