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Algebra-Please check my calculations

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Could you please check my answers and help with the ones I can't figure out-
1. Solution to the radical function sqrt(1/2x+1) = 1 is x = 0
True or False I think it is true according to my calculations

2.Solve x = sqrt(8x)
8x = x^2
x^2 - 8x = 0
x(x-8) = 0
x = 0
x-8 =0
x=8
the only solution is x = 0, correct or nobecause x = 8 doesn't work-
3. Simply (3x^2y^-2)^-2/9x^-5y
a.xy^3
b. xy^3/3
xy^3/9
d. xy^3/81

I think it is xy^3/81 but I'm not sure of my calculations

4. Solve 4sqrt(6x-2)>4
a. 1/3<=x<43
b. 1/3<x<43
x>=43
x>43
I think x>43
Thank you

  • Algebra-Please check my calculations - ,

    1. true if the equation is
    sqrt((1/2)x+1) = 1, or
    sqrt(x/2+1) = 1

    2. x=√(8x)
    "the only solution is x = 0, correct or nobecause x = 8 doesn't work- " ???
    x=0 works: 0=√(8*0)
    x=8 also works √(8*8)=8

    3. Correct.

    4. Solve 4sqrt(6x-2)>4
    Divide by 4 to get
    sqrt(6x-2)>1
    For this to happen, 6x-2>1 or x>(1/2)
    which does not match any of your answers.
    I suspect there is a misprint or misinterpretation of the question.

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