Posted by Rene on Tuesday, October 19, 2010 at 11:18am.
Let the lighter skater have mass M1 and velocity V1 after pushing off. For the heaver skater, use M2 and V2.
Because of conservation of momentum,
M1 V1 + M2 V2 = 0
V1/V2 = -M2/M1 = -2.833
(The minus sign just means they go in opposite drections)
They both travel equal distances to the end of the rink. The time to get there is inversely proportional to the velocity and proporitonal the mass.
T2/T1 = |V1/V2| = M2/M1 = 2.833
You know that T2 = 40 s
Solve for T1
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