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December 21, 2014

December 21, 2014

Posted by **Oswaldo** on Tuesday, October 19, 2010 at 11:01am.

- Calculus -
**MathMate**, Tuesday, October 19, 2010 at 11:37amIf x represents the side of each of the 4 little squares cut from the corners, then the dimensions of the box would be (180-2x), (180-2x) and x.

Volume,

V(x)=x(180-2x)²

Find V'(x)=dV(x)/dx and equate to zero. Solve for x. Retain only positive root, x0.

To make sure the value of x is maximum, Find V"(x)=d²V(x)/dx² and evaluate V"(x0).

If V"(x0)<0, V(x0) is at its maximum.

Post your answer for a check if you wish.

- Calculus -
**Anonymous**, Wednesday, March 30, 2011 at 10:11pm180

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