Posted by **Anonymous** on Tuesday, October 19, 2010 at 4:10am.

a bicycle turned upside down whiles owner repairs a flat tire. A friend spins the other wheel, of radius R, and observed that drops of water fly off tangentially. She measures the height reached by drops vertically. A drop that breaks loose from the tire on one turn rises a distance h1 above the tangent point. A drop that breaks loose on the next turn rises a distance h2>h1 above the tangent point. The height to which the drops rise decreases because the angular speed of the wheel decreases. From this information, determine the magnitude of the average angular acceleration of the wheel.

There is a figure in which is a picture of a bicycle wheel turned upside down, showing the height h from the center of the wheel to the first water drop (h1). There's also an arrow pointing that the wheel is turning clockwise.

- Physics -
**bobpursley**, Tuesday, October 19, 2010 at 8:37am
Your basic relationship is that angular speed times radius is tangental velocity

You can write tangental velocity in terms of h. Do that, then set it equal to wr

avg w= wf+wi /2 and you should have that now in terms of h1, h2

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