Wednesday

November 26, 2014

November 26, 2014

Posted by **Kamini** on Tuesday, October 19, 2010 at 1:56am.

- physics -
**drwls**, Tuesday, October 19, 2010 at 3:14amYou will need to consider both centripetal aceleration (a_r) and tangential acceleration (a_t), which are perpendicular.

3.50 = a_t^2 + a_c^2 = a_c^2 + 0.36

a_c^2 = V^2/R = 3.14 m/s^2

Solve for V when the acceleration of 3.50 m/s^2 is reached. From that, get the time and the number of revolutions

**Answer this Question**

**Related Questions**

physics - A car starts from rest on a curve with a radius of 130 m and ...

Physics - A car starts from rest on a curve with a radius of 130 m and ...

physics - A car starts from rest on a curve with a radius of 110 m and ...

College Physics - A car starts from rest on a curve with a radius of 150 m and ...

College Physics - A car starts from rest on a curve with a radius of 150 and ...

college physics - A car starts from rest on a curve with a radius of 190 and ...

Physic - A car starts from rest on a curve with a radius of 160 and accelerates ...

Physic - A car starts from rest on a curve with a radius of 160 and accelerates ...

college phyiscs - A car starts from rest on a curve with a radius of 160 m and ...

College Physics - A car starts from rest on a curve with a radius of 140 and ...