Homework Help: physics

Posted by Kamini on Tuesday, October 19, 2010 at 1:56am.

A car starts from rest on a curve with a radius of 190m and accelerates at 0.600m/s^2 . How many revolutions will the car have gone through when the magnitude of its total acceleration is 3.50m/s^2 ?

physics - drwls, Tuesday, October 19, 2010 at 3:14am
You will need to consider both centripetal aceleration (a_r) and tangential acceleration (a_t), which are perpendicular.
3.50 = a_t^2 + a_c^2 = a_c^2 + 0.36
a_c^2 = V^2/R = 3.14 m/s^2

Solve for V when the acceleration of 3.50 m/s^2 is reached. From that, get the time and the number of revolutions

Answer this Question

Related Questions

Physics - A car starts from rest on a curve with a radius of 130 m and ...
physics - A car starts from rest on a curve with a radius of 110 m and ...
physics - A car starts from rest on a curve with a radius of 130 m and ...
college physics - A car starts from rest on a curve with a radius of 190 and ...
College Physics - A car starts from rest on a curve with a radius of 150 m and ...
College Physics - A car starts from rest on a curve with a radius of 150 and ...
Physic - A car starts from rest on a curve with a radius of 160 and accelerates ...
Physic - A car starts from rest on a curve with a radius of 160 and accelerates ...
college phyiscs - A car starts from rest on a curve with a radius of 160 m and ...
physics - A car starts from rest on a curve with a radius of 120m and ...

For Further Reading

First Name:
School Subject:
Answer: