Posted by Diana on Tuesday, October 19, 2010 at 1:03am.
a) The applied horizontal force is balanced by the weight and the normal force applied to the block by the incline.
Let the normal force be Fn.
Fn = M g cos42 + F sin42
F cos42 = M g sin42
Solve for Fn
Fn = M g (cos42 + sin42*tan42) = 52.7 N
W = 39.2 N
b) F = 35.3 N
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