Calculate the theoretical amount of CaCl2 that would be required to change the temperature of 50ml of water from room temperature 20C to 45C? Remember heat loss during the dissolution is equal to the heat capacity of water. this value is 4.184. you assume that the density of the water is 1g/ml.
Chemistry - Jack, Monday, October 17, 2011 at 9:18pm
50 mL of Water
Ti = 20C
Tf = 45C
d = 1.00 g/mL
C = 4.184 J/g * C
50 mL * 1.00g/mL = 50 g
Delta T = 45-20 = 25 C
q = m * C * T
= (50) (4.184) (25)
= - 5230 J
-5230/-82800 = 0.061 mol
Molar mass of CaCl2 = 110.98 g/mol
0.061 mol * 110.98 g/mol = 6.77 g
Chemistry - susan, Wednesday, July 9, 2014 at 1:07pm
what does -82800 mean?
Chemistry - Alex, Sunday, October 25, 2015 at 12:46pm
In response to susan, the -82800 is the heat of solution for CaCl2 in joules.