Homework Help: Chemistry

Posted by Sarah on Tuesday, October 19, 2010 at 12:47am.

Calculate the theoretical amount of CaCl2 that would be required to change the temperature of 50ml of water from room temperature 20C to 45C? Remember heat loss during the dissolution is equal to the heat capacity of water. this value is 4.184. you assume that the density of the water is 1g/ml.

Chemistry - Jack, Monday, October 17, 2011 at 9:18pm
50 mL of Water
Ti = 20C
Tf = 45C
d = 1.00 g/mL
C = 4.184 J/g * C

50 mL * 1.00g/mL = 50 g

Delta T = 45-20 = 25 C

q = m * C * T

= (50) (4.184) (25)
= - 5230 J

-5230/-82800 = 0.061 mol
Molar mass of CaCl2 = 110.98 g/mol
0.061 mol * 110.98 g/mol = 6.77 g

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