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January 30, 2015

January 30, 2015

Posted by **A** on Monday, October 18, 2010 at 8:29pm.

- physics -
**bobpursley**, Monday, October 18, 2010 at 8:33pmstart with the fall from 1 m.

horizontal distance=horizontalvelociyt*time

where h= 1/2 g t^2 or t= sqrt 2h/g=sqrt 2/9.8

which means horizontal velociity is 1.6/sqrt(2/9.8)

now, having the horizontal velocity, use the conservation of momentum

(M+m)*horizontalvelocity= massbullet*v

solve for v

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