Posted by A on Monday, October 18, 2010 at 8:29pm.
start with the fall from 1 m.
horizontal distance=horizontalvelociyt*time
where h= 1/2 g t^2 or t= sqrt 2h/g=sqrt 2/9.8
which means horizontal velociity is 1.6/sqrt(2/9.8)
now, having the horizontal velocity, use the conservation of momentum
(M+m)*horizontalvelocity= massbullet*v
solve for v
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