Could someone please help me complete my lab experiment.

Antacid Brand: Life
Concentration of HCl: 0.1845 M
Concentration of NaOH: 0.1482 M

Trial 1:
1.Mass of Table: 1.2173g
2.Volume of HCl added: 75.0 mL
3.Milliomoles of HCl added:mmoles ? Help
4.Volume of NaOH used: 17.14 mL
5.Millimoles of NaOH used in titration:mmoles ? Help.
6.Millimoles of HCl that did not react with the antacid:mmoles ? Help.
7.mmoles of HCl neutralized by tablet:? Help.
8.mmoles of H+ neutralized per gram of antacid:mmoles/g ? Help.

Please help me with the questions I am having trouble with.

Thanks.

Well, moles = M x L

and millimiles = M x mL.

Could you look over my answers then, I am having trouble.

3. 13.8 mmoles
5. 11.1 mmoles

but for 6-8 I am still confused. How do I approach the problem?

Sure, I can help you with those questions. To answer these questions, you need to use the concept of stoichiometry and molar ratios. Here's how you can calculate the millimoles for each of the questions you mentioned:

Question 3: Millimoles of HCl added
To calculate this, you need to use the concentration of HCl and the volume of HCl added. The formula you can use is:

mmoles = concentration (M) * volume (L)

First, convert the volume from mL to L by dividing it by 1000:
75.0 mL = 75.0 mL / 1000 = 0.075 L

Then, substitute the values into the formula:
mmoles = 0.1845 M * 0.075 L

Calculate the result to obtain the millimoles of HCl added.

Question 5: Millimoles of NaOH used in titration
Similar to question 3, you use the concentration and volume of NaOH used. The formula is:

mmoles = concentration (M) * volume (L)

Convert the volume from mL to L:
17.14 mL = 17.14 mL / 1000 = 0.01714 L

Substitute the values into the formula:
mmoles = 0.1482 M * 0.01714 L

Calculate to obtain the millimoles of NaOH used in titration.

Question 6: Millimoles of HCl that did not react with the antacid
This can be calculated by subtracting the millimoles of NaOH used in titration from the millimoles of HCl added:

Millimoles of HCl that did not react = Millimoles of HCl added - Millimoles of NaOH used

Substitute the values you calculated for questions 3 and 5 to find the answer.

Question 7: Millimoles of HCl neutralized by tablet
Assuming that the NaOH reacts with the HCl in a 1:1 ratio, the millimoles of HCl neutralized by the tablet is equal to the millimoles of NaOH used in titration.

Question 8: Millimoles of H+ neutralized per gram of antacid
To calculate this, you need to divide the millimoles of HCl neutralized by the tablet by the mass of the tablet:

mmoles/g = Millimoles of HCl neutralized / Mass of tablet in grams

Substitute the values you calculated to find the answer.

Remember to perform these calculations for each trial separately if you have more than one trial.