Posted by **Preston** on Monday, October 18, 2010 at 7:36pm.

Find the slope of the tangent line to the curve y = (x^2 -8)^6 at x = 3, and

write the equation of the tangent line.

- Calculus -
**bobpursley**, Monday, October 18, 2010 at 7:45pm
Take the derivative.

y'=6(x^2-8)^5 * 2x

at x=3, put that in, and compute y'

equation: y=y' x + b

you have y'. you know x, and can compute y (original equation), so can compute b from that equation.

## Answer This Question

## Related Questions

- calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...
- Help Calc.! - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1...
- Calculus - Please help this is due tomorrow and I dont know how to Ive missed a ...
- please help; calc - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+...
- College Calculus - Let f(x) = 3x^2 - 2x + 1 a) write an equation of the line ...
- Calculus - 1) An equation of the line contains points (7/9, 7) and (-7/9) is 2) ...
- Need help fast on calc - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy...
- Math - Suppose f(x)=5/(x-2). f'(5)=-5/9. Use this to find the equation of the ...
- Calculus - I have a two part question that pertains to a curve (r(x)) and its ...
- Calculus - If F(x)=x^3−7x+5, use the limit definition of the derivative to...

More Related Questions