Calculus
posted by Preston .
Find the slope of the tangent line to the curve y = (x^2 8)^6 at x = 3, and
write the equation of the tangent line.

Take the derivative.
y'=6(x^28)^5 * 2x
at x=3, put that in, and compute y'
equation: y=y' x + b
you have y'. you know x, and can compute y (original equation), so can compute b from that equation.