Posted by Shea on .
How many moles of solute particles are present in 1 L of 1.20 M KBr?
mols = M x L
So we have 1.20 M x 1 L = 1.20 moles KBr. There are two particles/molecule; therefore, we have 1.20 x 2 = 2.40 moles of particles.