Calculate the temperature, in K, of 2.20 moles of gas occupying 3.50 L at 3.30 atm.
Use PV = nRT
To calculate the temperature, we can use the ideal gas law equation:
PV = nRT
where:
P is the pressure of the gas (in atm)
V is the volume of the gas (in liters)
n is the number of moles of gas
R is the ideal gas constant (0.0821 L·atm/mol·K)
T is the temperature of the gas (in Kelvin)
First, let's rearrange the equation to solve for temperature (T):
T = PV / (nR)
Now we can plug in the given values:
P = 3.30 atm
V = 3.50 L
n = 2.20 mol
R = 0.0821 L·atm/mol·K
T = (3.30 atm * 3.50 L) / (2.20 mol * 0.0821 L·atm/mol·K)
Simplifying the equation:
T = 12.6 atm⋅L / (0.18142 mol⋅atm/(L⋅K))
T = 69.44 K
Therefore, the temperature of 2.20 moles of gas occupying 3.50 L at 3.30 atm is 69.44 K.