At what temperature (oC) will a gas sample occupy 6.1 L if it originally occupies 17.8 L at 27.1oC?
I did (v1/t1)=(v2)/(t2)
v1=17.8
v2=6.1
t1=27.1 C = 300.25 K
the answer i got for t2= 102.894 K which would be -170.106 C
This doesnt seem right is it?