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Posted by on Sunday, October 17, 2010 at 6:54pm.

How much work is required to stop an electron (m= 9.11 * 10^-31 kg) which is moving with a speed of 1.80×10^6 m/s?

  • Physics - , Sunday, October 17, 2010 at 6:59pm

    The work done ON the electron is negative, and equals the initial kinetic energy, (1/2)m*V^2.
    Use V in m/s and m in kg and the answer will be in Joules.

  • Physics - , Sunday, January 11, 2015 at 2:25pm

    45.6 J

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