Posted by **mary- please show correct calculations** on Sunday, October 17, 2010 at 3:59pm.

for a particular sample of 77 scores on a psychology exam, the following results were obtained:

first quartile=44, third quartile= 71, standard deviation=6, range=45, mean=64,median=57, mode=32, midrange=60

a)according to chevyshev's theorem how many students scored between 48 and 88?

b) assume that the distribution is normal. based on the empirical rule, how many students scored between 46 and 82?

* i came up with 12 for a and 24 for b, is that correct?

please help and show where i went wrong. thank you

- statistics -
**PsyDAG**, Monday, October 18, 2010 at 3:41pm
From the data, mode = 32, median = 57 and mean 64, the distribution is definitely positively skewed (to the right).

Unfortunately, I don't know Chevyshev's theorem, and I would not assume the distribution to be normal.

However, for a normal distribution, Z = (score-mean)/SD

Find the Z scores for 46 and 82, then Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions related to those Z scores and multiply those proportions by 77.

## Answer This Question

## Related Questions

- statistics - for a particular sample of 77 scores on a psychology exam the ...
- statistics - For a particular sample of 71 scores on a psychology exam, the ...
- statistics - For a particular sample of 53 scores on a psychology exam, the ...
- statistics - For a particular sample of 63 scores on a psychology exam, the ...
- statistics - For a particular sample of 80 scores on a psychology exam, the ...
- statistics - For a particular sample of 63 scores on a psychology exam, the ...
- Statistics - For a particular sample of 63 scores on a psychology exam, the ...
- Statistics - For a particular sample of 63 scores on a psychology exam, the ...
- Stats - For a particular sample of 63 scores on a psychology exam, the following...
- Stats - For a particular sample of 63 scores on a psychology exam, the following...

More Related Questions