A balloon is filled with 2.3 cm3 helium gas at 112.1 atm pressure. What will be the new pressure (atm) if the volume is changed to 44.7 cm3?
P1V1=P2V2
(112.1)(.0023)=(P2)(.0447)
the answer i got was 54.85
so would the answer be 54.85 atm?
I believe you punched in the numbers wrong. I get something like 5.8 atm.
Yes, you are correct. Using the formula P1V1 = P2V2, where P1 is the initial pressure, V1 is the initial volume, P2 is the new pressure, and V2 is the new volume, you can solve for P2.
Plugging in the given values:
P1 = 112.1 atm (initial pressure)
V1 = 2.3 cm^3 (initial volume)
V2 = 44.7 cm^3 (new volume)
Setting up the equation:
112.1 x 2.3 = P2 x 44.7
Simplifying:
257.73 = 44.7P2
Dividing both sides by 44.7:
P2 ≈ 5.77 atm
So the new pressure, when the volume is changed to 44.7 cm^3, would be approximately 5.77 atm, not 54.85 atm.