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Assume that alpha is an angle in the standard position whose terminal side contains the given point. Find the exact values of
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To find the exact values of the trigonometric functions for an angle in standard position, we must
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Assume that alpha is an angle in the standard position whose terminal side contains the given point. Find the exact values of
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To find the exact values of the trigonometric functions, we need to determine the lengths of the
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Assume that alpha is an angle in the standard position whose terminal side contains the given point. Find the exact values of
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To find the values of the trigonometric functions for an angle in standard position, we can use the
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FInd the exact value pf the 6 trig function of alpha
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(0,0), (-2,-6). X = -2-0 = -2. Y = -6-0 = -6. r = sqrt((-2)^2+(-6)^2) = sqrt40 = sqrt(4*10) =
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if sin alpha is 0.28° where 0° is less than or equal to alpha less than or equal to 90°, evaluate cos alpha, tan alpha, sec
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I'll use a for alpha. sin(a) is not measured in degrees. sin a = 0.28 since sin^2+cos^2=1, cos a =
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Why is the output of the code 14, not 8 : alpha=3+5=8?
public class Application4{ public static void main(String[] args) { int
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I think you forgot a <u>break;</u> statement, so calculation falls through to the next step.
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when solving for all solutions how do I work out this problem: cos4(alpha)=cos2(alpha)
and when verifying each identity how do I
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cos4x = cos2x 2cos^2(2x)-1 = cos2x 2cos^2(2x)-cos(2x)-1 = 1 (2cos2x+1)(cos2x-1) = 0 so, cos2x = -1/2
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Factorthen use fundamental identities to simplify the expression below and determine which of the following is not equivalent
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We conducted a hypothesis test for a population parameter at alpha = 0.05 and we failed to rejected Ho.
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See Previous post.
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We conducted a hypothesis test for a population parameter at alpha = 0.01 and we failed to rejected Ho.
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C. Is the .05 > Alpha > .01? We don’t know.
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