Physics
posted by Daniel on .
A 25 kg chain initially at rest on a horizontal floor requires a 365 N horizontal force to set it in motion. Once the chair is in motion, a 327 N horizontal force keeps it moving at a constant velocity.
a. Find the coefficient of static friction between the chain and floor.
b. Find the coefficient of kinetic friction between the chair and the floor.
I have a lot of problems like these but I just need to know how to do one to figure them all out, thanks in advance.

friction force=365N if in constant velocity
mu*m*g=365 solve for mu
mu=m*g=327 solve for mu. 
The static friction is 1.5
The kinetic friction is 1.3