Dave rides his motorcycle off the rim of the Snake River Canyon at a horizontal velocity of 54 meters per second. how far has he dropped (meters) into the canyonin 1.48 seconds? NOTE: assume he does not hit the bottom.

h=1/2 g t^2 horizontal velocity does not change falling time.

A car rolls off the edge of the Grand Canyon with a velocity of 16.14 m/s. How far in meters down into the canyon has it traveled in 0.71 seconds

To determine how far Dave has dropped into the canyon in 1.48 seconds, we can use the equations of motion.

The equation that relates an object's displacement (drop distance), initial velocity, time, and acceleration is:
displacement = initial velocity * time + 0.5 * acceleration * time^2

In this case, we are given the initial horizontal velocity (54 m/s) and the time (1.48 seconds). However, we are not given the acceleration directly.

Since Dave rides his motorcycle off the rim without hitting the bottom, we can assume that he is in free fall, experiencing only the acceleration due to gravity (9.8 m/s^2).

Plugging in the values into the equation, we have:
displacement = 54 m/s * 1.48 s + 0.5 * 9.8 m/s^2 * (1.48 s)^2

Simplifying this equation will give us the answer.