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September 17, 2014

September 17, 2014

Posted by **Nick** on Sunday, October 17, 2010 at 3:41am.

Please help.

- Math -
**drwls**, Sunday, October 17, 2010 at 6:28amI'm sorry, but the integrand

"2x^2 to x-5 of square root of Sin(t)dt."

does not make sense.

In general, the derivative of an indefinite integral of a function is the function itself.

- Math -
**Nick**, Monday, October 18, 2010 at 8:12amOk, so if I change it to 2x^2 to x-5 of square root of Sin(x)dx, does it make sense?

We haven't done any examples with an x in both the top and bottom of the integral sign.

Thanks

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