Write the condensed ground-stste electron configuration of the transition metal ion Mo3+

[Kr]5s24d1

To determine the condensed ground-state electron configuration of the transition metal ion Mo3+, you'll need to know the electron configuration of the neutral atom, molybdenum (Mo).

The electron configuration of neutral molybdenum (Mo) is: [Kr] 5s^2 4d^5

To obtain the electron configuration of Mo3+, you'll need to remove three electrons from the neutral atom. In general, when removing electrons from the neutral atom to form an ion, the outermost electrons are removed first.

Therefore, the electron removal will happen from the 5s orbital, followed by the 4d orbital. Starting with the 5s^2 4d^5 configuration, we remove three electrons.

The condensed ground-state electron configuration of Mo3+ is:
[Kr] 4d^3

Here's the step-by-step breakdown:

1. Start with the electron configuration of neutral molybdenum (Mo): [Kr] 5s^2 4d^5
2. Remove three electrons from the outermost orbitals:
- First, remove the electrons from the 5s orbital: [Kr] 4d^5
- Then, remove the remaining electrons from the 4d orbital: [Kr] 4d^3
3. Condense the electron configuration by replacing the noble gas, krypton (Kr), with its symbol: [Kr] 4d^3

So, the condensed ground-state electron configuration of the Mo3+ ion is [Kr] 4d^3.