The greater of two consecutive integers is 15 more than twice the smaller. Find the integers.

amogus

n+1-15=2n

solve for n, and n+1

To solve this problem, we can break it down into two steps:

Step 1: Set up the equations
Let's assume that the two consecutive integers are x and x+1.

According to the problem, the greater of these two consecutive integers is 15 more than twice the smaller. We can write this as an equation:

x+1 = 2x + 15

Step 2: Solve the equation
Now we can solve the equation to find the values of x and x+1.

Subtract x from both sides of the equation:

1 = x + 15

Subtract 15 from both sides:

x = -14

So the smaller of the two consecutive integers is -14. Plugging this back into our assumption, the greater integer is:

x+1 = -14 + 1 = -13

Therefore, the two consecutive integers are -14 and -13.