The greater of two consecutive integers is 15 more than twice the smaller. Find the integers.
amogus
n+1-15=2n
solve for n, and n+1
To solve this problem, we can break it down into two steps:
Step 1: Set up the equations
Let's assume that the two consecutive integers are x and x+1.
According to the problem, the greater of these two consecutive integers is 15 more than twice the smaller. We can write this as an equation:
x+1 = 2x + 15
Step 2: Solve the equation
Now we can solve the equation to find the values of x and x+1.
Subtract x from both sides of the equation:
1 = x + 15
Subtract 15 from both sides:
x = -14
So the smaller of the two consecutive integers is -14. Plugging this back into our assumption, the greater integer is:
x+1 = -14 + 1 = -13
Therefore, the two consecutive integers are -14 and -13.