Posted by jo on Saturday, October 16, 2010 at 8:01pm.
1) Solve this equation for angular velocity w (radians per second), then convert w to rpm
R*w^2 = 6500*g
R = 0.05 m.
g = 9.8 m/s^2
w = sqrt[6500(g/R)]
2. Let U be the coefficient of syatice friction
M g U = M Rw^2
U = R w^2/g
If the period is P = 1.8 s,
w = 2 pi/P = 3.49 rad/s
a. a= 6500*9.8m/s
a= w^2/r solve for w
w is in radians/second, so you have to change that to rev/min (1/(2PI*60)
b. w=2PI/1.8
centripetal force wants requires the following force to keep it in place
force needed=mw^2/r
but friction to provide this is mu*mg
mu*mg=m*w^2/r
solve for mu
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