If aqueous hydrofluoric acid is reacted with sodium hydroxide, which of the following substances are in the net ionic equation?

1. fluoride ion, hydronium ion, and water
2. fluoride ion, hydroxide ion, hydronium ion, and water
3. hydrofluoric acid, sodium ion, hydroxide ion, and fluoride ion
4. hydrofluoric acid, hydroxide ion, hydronium ion, fluoride ion, and water
5. hydrofluoric acid, hydroxide ion, fluoride ion, and water

HF(aq) + NaOH(aq) ==> NaF + H2O

Net ionic is
HF(aq) + OH^-(aq) ==> F^-(aq) + H2O(l)

To determine the substances in the net ionic equation, we need to firstly write the balanced chemical equation for the reaction between aqueous hydrofluoric acid and sodium hydroxide.

The balanced chemical equation for the reaction is:

HF(aq) + NaOH(aq) → NaF(aq) + H2O(l)

To identify the substances in the net ionic equation, we need to separate the complete ionic equation into its constituent ions and eliminate the spectator ions. Spectator ions are the ions that appear on both sides of the equation and do not participate in the reaction.

The complete ionic equation for the reaction is:

H+(aq) + F-(aq) + Na+(aq) + OH-(aq) → Na+(aq) + F-(aq) + H2O(l)

In this reaction, Na+(aq) and F-(aq) appear on both sides of the equation and do not change, so they are spectator ions.

Hence, the net ionic equation for the reaction is:

H+(aq) + OH-(aq) → H2O(l)

From the net ionic equation, we can see that the substances involved are hydroxide ion (OH-), hydronium ion (H+), and water (H2O).

Therefore, the answer is:

2. fluoride ion, hydroxide ion, hydronium ion, and water