a fasrmer has 46 animals.He has fewer 6 sheep than pigs. how many pigs does he have?

does he have only sheep and pigs??

pigs --- x
sheep --- x-6

solve

x + x-6 = 46

46-6=40

40 / 2 = 20
20+6= 26

To solve this problem, we can set up an equation. Let's represent the number of pigs as "x".

We are given that the farmer has 46 animals, and that he has 6 fewer sheep than pigs. Since we don't know the number of sheep, we'll represent it as "x - 6".

The total number of animals can be expressed as the sum of the number of pigs and the number of sheep:

x + (x - 6) = 46

Simplifying the equation, we combine like terms:

2x - 6 = 46

Next, we isolate the variable on one side of the equation.

Adding 6 to both sides of the equation:

2x = 46 + 6

2x = 52

Finally, we solve for x by dividing both sides of the equation by 2:

x = 52 / 2

x = 26

Therefore, the farmer has 26 pigs.