Algebra 2
posted by Ren on .
can someone show me how to do it step by step please!
Use a graph and table to solve each system. check your answer
{y+x=5
{3x5y=1

x + y = 5,
3x  5y = 1,
I will use the elimination method which
eliminates 1 variable and allows me to solve for the other.
Step 1. Multiply both sides of the 1st Eq by 3 and add the 2 Eqs:
3x  3y = 15,
3x  5y = 1,
0  8y = 16,
 8y =  16,
Step 2. Divide both sides by 8 and get:
y = 2.
Step 3. Substitute 2 for y in Eq 1
and solve for x:
x + 2  5,
x = 5  2,
x = 3.
Solution set:(x , y) = (3 , 2) = The
point where the 2 graphs will intersect.
To graph the Eqs, use the following
convenient points:
x + y = 5. (0 , 5) , (2 , 3) , (5 ,0).
3x  5y = 1. (2 , 1) , (3 , 2) ,
(5 , 3.2).
I hope this will help. 
CORRECTION: The 1st Eq under Step 3
should read: x + 2 = 5.