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January 31, 2015

January 31, 2015

Posted by **Emily** on Friday, October 15, 2010 at 7:10pm.

Show that the "value of 3x^2-6x+5" cannot be less than 1. ?

- Math -
**bobpursley**, Friday, October 15, 2010 at 7:17pmshow the opposite: the value is <1

3x^2-6x+5<1

3x^2-6x+4<0

x= (6+-sqrt(36-48))/6

well the serd here is imaginary. So the assumption of being less than one is false.

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