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Posted by on Friday, October 15, 2010 at 2:04am.

Integrate x^2+5x+1dx/(2x^3+15x^2+6x+23)^1/2

  • calculus - , Friday, October 15, 2010 at 7:42am

    Let 2x^3+15x^2+6x+23 = u
    du = 6x^2 + 30x + 6
    = 6(x^2 + 5x + 1)dx
    You got lucky with this one!
    Therefore the integrand can be written
    (1/6)du/u^1/2
    and the integral is
    (1/3)*u^1/2
    = (1/3)(2x^3+15x^2+6x+23)^1/2

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