Posted by br0Ok3 on Friday, October 15, 2010 at 1:12am.
A basketball player has a 76% chance of making a free throw. What is the probability of her making 104 or more free throws in 119 trials? Round your standard normal variable to two decimal places before using the table of values.

statistics  MathGuru, Friday, October 15, 2010 at 7:40pm
Use the normal approximation to the binomial distribution.
Your values are the following:
p = .76, q = 1  p = .24, x = 104, and n = 119
Find mean and standard deviation.
mean = np = (119)(.76) = ?
sd = √npq = √(119)(.76)(.24) = ?
Once you calculate the mean and standard deviation, find zscore:
z = (x  mean)/sd
Once you have the zscore, check the ztable for the probability. Remember the question is asking the probability of 104 or more.
I hope this will help get you started.
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