posted by br0Ok3 on .
A basketball player has a 76% chance of making a free throw. What is the probability of her making 104 or more free throws in 119 trials? Round your standard normal variable to two decimal places before using the table of values.
Use the normal approximation to the binomial distribution.
Your values are the following:
p = .76, q = 1 - p = .24, x = 104, and n = 119
Find mean and standard deviation.
mean = np = (119)(.76) = ?
sd = √npq = √(119)(.76)(.24) = ?
Once you calculate the mean and standard deviation, find z-score:
z = (x - mean)/sd
Once you have the z-score, check the z-table for the probability. Remember the question is asking the probability of 104 or more.
I hope this will help get you started.