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September 23, 2014

September 23, 2014

Posted by **jenny** on Friday, October 15, 2010 at 12:49am.

make a table showing the areas for some selected values of x, and write a function that gives the area, y, as a function of the width, x

- algebra 2 -
**drwls**, Friday, October 15, 2010 at 8:14amLet x be the width of the side parallel to the building. The other two sides then have length (80-x)/2

The area is y = x(40 - x/2)

y = 40x - (x^2/2)

You get maximum area when dy/dx = 0

40 -x = 0

x = 40

Table:

x y

20 600

30 750

39 799.5

40 800

41 799.5

50 750

60 600

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