posted by John on .
A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is 0.24 and the push imparts an initial speed of 3.8 m/s?
u_k = 0.24
Vo = 3.8
It will travel a distance X such that
Friction work = initial kinetic energy
F(friction)*X = u_k*M*g*X = (1/2)M Vo^2
Mass M cancels out.
X = Vo^2/(2*u_k*g)= 3.1 meters