Posted by John on Thursday, October 14, 2010 at 11:45pm.
u_k = 0.24
Vo = 3.8
It will travel a distance X such that
Friction work = initial kinetic energy
F(friction)*X = u_k*M*g*X = (1/2)M Vo^2
Mass M cancels out.
X = Vo^2/(2*u_k*g)= 3.1 meters
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