How many atoms of element "R" are present in 55.80 g of (AH3)4(R2O3)4 (molar mass = 478.17 g/mol)?
Please help. I've tried going (g of molecule/mol)x(1 mol of molecule/ 55.80g)but I'm not really sure what to do with this.
To calculate the number of atoms of element "R" present in the given compound (AH3)4(R2O3)4, you need to follow a step-by-step approach:
Step 1: Determine the molar mass of the compound:
The molar mass of (AH3)4(R2O3)4 is given as 478.17 g/mol.
Step 2: Calculate the number of moles:
To determine the number of moles in 55.80 g of the compound, use the formula:
Number of moles = Mass of the compound / Molar mass
In this case, it would be:
Number of moles = 55.80 g / 478.17 g/mol
Step 3: Find the molar ratio between "R" and the compound:
The compound contains (AH3)4(R2O3)4, which means there are four "R" atoms present in each molecule of the compound.
Step 4: Calculate the number of atoms of element "R":
To determine the number of atoms of element "R," multiply the number of moles of the compound (from Step 2) by Avogadro's number (6.022 × 10^23) and then by the molar ratio of "R" (4) within one molecule of the compound.
Number of atoms of "R" = Number of moles × Avogadro's number × molar ratio
So, the final calculation would be:
Number of atoms of "R" = Number of moles × 6.022 × 10^23 × 4
Now, you can substitute the value of the number of moles (from Step 2) into the equation to calculate the number of atoms of element "R."